﻿WEBVTT

00:00:16.100 --> 00:00:24.966
Welcome everybody! Today we will present to you a feature of the iOrgChem
website, specifically how to practice with the assignment of chirality

00:00:24.966 --> 00:00:32.099
more specifically, how to practice with the
assignment of chirality of R or S configurations

00:00:32.100 --> 00:00:35.900
Let's start by opening the web page...

00:00:35.900 --> 00:00:44.733
...and on the horizontal menu, at the item Exercises, choose
the sub-item "Chirality? Hands on! A step-by-step guide"

00:00:46.900 --> 00:00:58.733
We can see two panels: in the left one we can draw a molecule in
2D and in the right one we wiil be able to see the 3D molecule

00:00:58.733 --> 00:01:10.633
just on the right we have the possibiltiy to select the background colour
for the 3D panel: white or black to have a better contrast of the image

00:01:10.633 --> 00:01:20.899
at the right edge we have several buttons, useful to practice
assigning the chirality with a "step-by-step" method.

00:01:20.900 --> 00:01:26.766
By scrolling down the page by the mouse...

00:01:26.766 --> 00:01:38.332
...we can see some instructions to be followed, for a proficient use of
the page, by assigning the R or S configuration and check the results.

00:01:38.333 --> 00:01:42.733
finally, some sections are reported below:

00:01:42.733 --> 00:01:50.566
1) Sequence Rules; 2) Correct Oreintation of
the Molecule; 3) Configuration Assignment

00:01:50.566 --> 00:01:59.266
by clicking on them you can find information for
the configruation assignment of a chiral carbon

00:02:03.066 --> 00:02:13.099
Let's start by drawing a simple molecule with
a carbon substituted by four different groups...

00:02:13.100 --> 00:02:17.100
...a propyl group....

00:02:17.100 --> 00:02:21.100
...a hydroxyl group...

00:02:21.100 --> 00:02:23.533
...a methyl group...

00:02:23.533 --> 00:02:26.066
...and a chlorine atom

00:02:26.066 --> 00:02:31.799
If we want to be precise, like when we are
drawing molecules taken from a book...

00:02:31.800 --> 00:02:40.633
we "must" take care to draw the molecule in a correct way, in
particular the stereochemical bonds, wedged and hash-wedged!

00:02:40.633 --> 00:02:51.666
In this case, we can draw the wedged bond connecting the chiral
carbon to the hydroxy group and the hash-wedged one for the chlorine

00:02:51.666 --> 00:02:59.566
Once we have finshed drawing the molecule
we can select the button "2D to 3D"...

00:02:59.566 --> 00:03:04.699
...and the 3D structure will appear in
the right panel in a few seconds.

00:03:07.100 --> 00:03:11.100
first of all, let's click on the
"initialize" button to set up the process.

00:03:11.100 --> 00:03:16.700
...and select the chiral carbon by the mouse.

00:03:16.700 --> 00:03:20.700
Please pay attention "NOT" to rotate/move the
molecule, otherwise the atom will not be selected!

00:03:20.700 --> 00:03:26.900
By clicking with the mouse left button on the "C"
button the "C" label will appear on the chiral center

00:03:26.900 --> 00:03:36.400
Once we have defined the chiral center, we can use the same
method to attribute the priority to the four substituents...

00:03:36.400 --> 00:03:43.366
so, click on the chlorine and
attribute to it the priority "1"...

00:03:43.366 --> 00:03:47.366
...priority "2" to the hydroxyl group...

00:03:47.366 --> 00:03:50.766
...priority "3" to the propyl group...

00:03:50.766 --> 00:03:54.766
...and priority "4" to the methyl group...

00:03:54.766 --> 00:04:05.032
pay attention: the propyl has higher priority than the methyl group:
its first carbon is connected to a carbon while methyl has only hydrogens.

00:04:05.033 --> 00:04:18.833
Now we have to move the molecule to orient it with lowest
priority group (methyl) pointing away from the observer.

00:04:24.133 --> 00:04:27.533
Now we are ready to assign the chirality!

00:04:27.533 --> 00:04:39.299
to do it, let's have a look at the priority order. In order to go from
1 → 2 → 3, we need to follow a counterclockwise direction. Chirality is "S"

00:04:39.300 --> 00:04:44.766
in order to assign chirality, select
the chiral carbon with the mouse...

00:04:44.766 --> 00:04:50.832
...and click on the "S" button

00:04:50.833 --> 00:05:03.699
To check our answer about chirality, let's click
with the mouse on the "Check Chirality" button.

00:05:03.700 --> 00:05:12.966
If the letter (R or S) we have drawn before on the chiral
carbon does not change, we assigned the correct chirality....

00:05:12.966 --> 00:05:15.299
...otherwise, it will be incorrect.

00:05:15.300 --> 00:05:24.200
In this case, we are warmly suggested to check: 1) the priority
we assigned before; 2) the orientation of the molecule.

00:05:24.200 --> 00:05:38.433
If we simply want to know the chirality, we can
click on the "Show All Chiral Carbons" button.

00:05:38.433 --> 00:05:48.733
If there is more than one chiral carbon, we will be presented
with the chirality assignment of all chiral carbons.

00:05:50.700 --> 00:06:01.900
We can advise you to see the two videos: "The chirality"
and "The structural isomerism" (only in italian)

00:06:01.900 --> 00:06:06.900
Have a good study time!
